a new built-in function, enumerate() , will make certain loops a bit clearer. enumerate(thing) , whereis either an iterator or a sequence, returns a iterator that will return (0,[0]) , (1,[1]) , (2,[2]) , and so forth.

a common idiom to change every element of a list looks like this:

用法:在同时需要index 和 value 值得时候可以使用

line = [1,3,’dfd’,’jdjfjd’]
for i in range(len(line)):
item = line[i]
—> 1
—> 3
—> dfd
—> jdjfjd


line = [1,3,’dfd’,’jdjfjd’]
for i,item in enumerate(line):
print(i,”——-“,item)enumerate 实战

line 是个 string 包含 0 和 1,要把1都找出来:


def read_line(line):

sample = {}

n = len(line)

for i in range(n):

if line[i]!=’0′:

sample[i] = int(line[i])

return sample


def xread_line(line):

return((idx,int(val)) for idx, val in enumerate(line) if val != ‘0’)

print read_line(‘0001110101’)

print list(xread_line(‘0001110101’))

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